The reaction sequence is as follows: CH(COOK) | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) $1$. The electrolysis of an aqueous solution of potassium maleate (or fumarate) is a Kolbe electrolysis reaction.$2$. The reaction is: $CH(COOK)=C

Vedclass · Accepted Answer

$CH_3-CH=O$

Vedclass · Answer

(A) $1$. The electrolysis of an aqueous solution of potassium maleate (or fumarate) is a Kolbe electrolysis reaction.$2$. The reaction is: $CH(COOK)=CH(COOK) + 2H_2O \xrightarrow{	ext{electrolysis}} CH \equiv CH + 2CO_2 + H_2 + 2KOH$.$3$. Thus,$X$ is acetylene $(CH \equiv CH)$.$4$. The hydration of acetylene in the presence of $Hg^{2+}$ and $dil. H_2SO_4$ (Kucherov reaction) yields acetaldehyde $(CH_3CHO)$.$5$. The reaction is: $CH \equiv CH + H_2O$ $\xrightarrow{Hg^{2+}/H_2SO_4} [CH_2=CH-OH]$ $ightarrow CH_3-CH=O$.$6$. Therefore,$Y$ is $CH_3-CH=O$.

The reaction sequence is as follows:
$CH(COOK)=CH(COOK)_{(aq)}$ $\xrightarrow{\text{electrolysis}} X$ $\xrightarrow[Hg^{2+}]{dil. H_2SO_4} Y$; $Y$ is

Similar Questions

The reaction of $2-$pentyne with dilute $H_2SO_4$ and $HgSO_4$ yields...............

Acetylene reacts with ammoniacal $AgNO_{3}$ to form:

Carbon-carbon bond length is minimum in

When propyne reacts with aqueous $H_2SO_4$ in the presence of $HgSO_4$,the major product is

In the given reactions,find the sum of $(x + y)$.
$(1)$ $Ph-C(Br)_2-CH_3$ $\xrightarrow{xNaNH_2} (A)$ $\xrightarrow{CH_3I} Ph-C \equiv C-CH_3$
$(2)$ $CH_3-CH_2-C(Br)_2-CH_3 \xrightarrow{yNaNH_2} CH_3-C \equiv C-CH_3$
Find the value of $(x + y)$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module

The reaction sequence is as follows: $CH(COOK)=CH(COOK)_{(aq)}$ $\xrightarrow{\text{electrolysis}} X$ $\xrightarrow[Hg^{2+}]{dil. H_2SO_4} Y$; $Y$ is