TV waves have a wavelength range of 1-10 , m. | vedclass

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Question

(A) The relationship between frequency $(v)$,speed of light $(c)$,and wavelength $(\lambda)$ is given by $v = \frac{c}{\lambda}$.Given $c = 3 	imes 1

Vedclass · Accepted Answer

$30-300$

Vedclass · Answer

(A) The relationship between frequency $(v)$,speed of light $(c)$,and wavelength $(\lambda)$ is given by $v = \frac{c}{\lambda}$.Given $c = 3 	imes 10^8 \, m/s$.For $\lambda_1 = 1 \, m$,the frequency is $v_1 = \frac{3 	imes 10^8}{1} = 3 	imes 10^8 \, Hz = 300 \, MHz$.For $\lambda_2 = 10 \, m$,the frequency is $v_2 = \frac{3 	imes 10^8}{10} = 3 	imes 10^7 \, Hz = 30 \, MHz$.Thus,the frequency range is $30-300 \, MHz$.

$TV$ waves have a wavelength range of $1-10 \, m$. Their frequency range in $MHz$ is

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