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(C) The law of reciprocal proportions states that if two different elements combine separately with a fixed mass of a third element,the ratio of the m

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Reciprocal proportions

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(C) The law of reciprocal proportions states that if two different elements combine separately with a fixed mass of a third element,the ratio of the masses in which they do so are either the same as or a simple multiple of the ratio of the masses in which they combine with each other.In the given data:$1$. Hydrogen $(H)$ combines with Oxygen $(O)$ to form $H_2O$: $2 \ g$ of $H$ with $16 \ g$ of $O$.$2$. Hydrogen $(H)$ combines with Carbon $(C)$ to form $CH_4$: $2 \ g$ of $H$ with $6 \ g$ of $C$.$3$. Carbon $(C)$ combines with Oxygen $(O)$ to form $CO_2$: $12 \ g$ of $C$ with $32 \ g$ of $O$,which means $6 \ g$ of $C$ combines with $16 \ g$ of $O$.The ratio of masses of $C$ and $O$ combining with a fixed mass of $H$ $(2 \ g)$ is $6:16$ or $3:8$.This ratio is the same as the ratio in which $C$ and $O$ combine with each other ($6 \ g$ of $C$ with $16 \ g$ of $O$).Thus,this illustrates the law of reciprocal proportions.

$2 \ g$ of hydrogen combine with $16 \ g$ of oxygen to form water and with $6 \ g$ of carbon to form methane. In carbon dioxide,$12 \ g$ of carbon are combined with $32 \ g$ of oxygen. These figures illustrate the law of:

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