100 mL of PH_3 on decomposition produces pho | vedclass

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(A) The balanced chemical equation for the decomposition of phosphine is: $2PH_{3(g)} 	o 2P_{(s)} + 3H_{2(g)}$ According to the stoichiometry of the

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$50$

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(A) The balanced chemical equation for the decomposition of phosphine is: $2PH_{3(g)} 	o 2P_{(s)} + 3H_{2(g)}$ According to the stoichiometry of the reaction,$2 \ mL$ of $PH_3$ gas produces $3 \ mL$ of $H_2$ gas,while phosphorus is formed as a solid. For $100 \ mL$ of $PH_3$,the volume of $H_2$ produced is: $V_{H_2} = \frac{3}{2} 	imes 100 \ mL = 150 \ mL$ The change in volume is the difference between the final volume of gas and the initial volume of gas: $	ext{Increase in volume} = 150 \ mL - 100 \ mL = 50 \ mL$.

$100 \ mL$ of $PH_3$ on decomposition produces phosphorus and hydrogen. The change in volume is ............... $mL$ increase.

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