$[Ni(CO)_4]$ is diamagnetic. Which of the following statements is correct for this complex?

  • A
    $C-O$ bond length increases during complex formation compared to isolated $CO$
  • B
    $CO$ acts as a strong field ligand
  • C
    The complex has a tetrahedral geometry
  • D
    All of the above are correct

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Similar Questions

The reaction of $K_3[Fe(CN)_6]$ with freshly prepared $FeSO_4$ solution produces a dark blue precipitate called Turnbull's blue. The reaction of $K_4[Fe(CN)_6]$ with $FeSO_4$ solution in the complete absence of air produces a white precipitate $X$,which turns blue in air. Mixing the $FeSO_4$ solution with $NaNO_3$,followed by a slow addition of concentrated $H_2SO_4$ through the side of the test tube,produces a brown ring.
Precipitate $X$ is:
$(A)$ $Fe_4[Fe(CN)_6]_3$
$(B)$ $Fe[Fe(CN)_6]$
$(C)$ $K_2Fe[Fe(CN)_6]$
$(D)$ $KFe[Fe(CN)_6]$
Among the following,the brown ring is due to the formation of:
$(A)$ $[Fe(NO)_2(SO_4)_2]^{2-}$
$(B)$ $[Fe(NO)_2(H_2O)_4]^{3+}$
$(C)$ $[Fe(NO)_4(SO_4)_2]$
$(D)$ $[Fe(H_2O)_5(NO)]SO_4$

Match List-$I$ with List-$II$ and select the correct code:
List-$I$ List-$II$
$A$. Ziegler-Natta $i$. $Fe_4[Fe(CN)_6]_3$
$B$. Brown ring complex $ii$. $[Fe(H_2O)_5NO]SO_4$
$C$. Prussian Blue $iii$. $Al(C_2H_5)_3 + TiCl_4$
$D$. Turnbull Blue $iv$. $Fe_3[Fe(CN)_6]_2$

Correct code is:

Which of the following orders is not correct?

Identify the correct set from the following table:

The correct statements from the following are:
$A$. The strength of anionic ligands can be explained by crystal field theory.
$B$. Valence bond theory does not give a quantitative interpretation of kinetic stability of coordination compounds.
$C$. The hybridization involved in the formation of $\left[Ni(CN)_4\right]^{2-}$ complex is $dsp^2$.
$D$. The number of possible isomer$(s)$ of $cis-\left[PtCl_2(en)_2\right]^{2+}$ is one.
Choose the correct answer from the options given below:

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