$11.1 \ g$ of $CaCl_2$ is dissolved in $1 \ kg$ of water. Determine the elevation in boiling point of the solution. $[K_b = 0.5 \ K \ kg \ mol^{-1}]$ :-

$18 \, g$ of glucose $(C_{6}H_{12}O_{6})$ dissolved in $1 \, kg$ of water is heated to boiling. The boiling point (in $K$) measured at $1 \, atm$ pressure is closest to: [Ebullioscopic constant,$K_{b}$ for water is $0.52 \, K \, kg \, mol^{-1}$. Consider the boiling point of pure water to be $373.15 \, K$]

Which one of the following would produce maximum elevation in boiling point?

Which of the following statements is correct for the boiling point of a solvent containing a dissolved solid substance?

If $10 \ g$ of a solute (molar mass $= 100 \ g/mol$) is dissolved in $100 \ g$ of water,then the molal elevation constant $K_b$ of the solvent will be equal to:

$A$ solution containing $0.1050 \ g$ of a substance in $15.84 \ g$ of ether has a boiling point $1 \ ^\circ C$ higher than that of pure ether. What is the molar mass of the substance? [Given: Molar elevation constant for ether per $100 \ g = 21.6$]