C_2H_5Br xrightarrow{KCN} A xrightarrow{text{ | vedclass

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(D) The reaction is a nucleophilic substitution reaction.$C_2H_5Br + KCN \rightarrow C_2H_5CN + KBr$Here,$C_2H_5Br$ (Ethyl bromide) reacts with $KCN$

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Ethyl cyanide

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(D) The reaction is a nucleophilic substitution reaction.$C_2H_5Br + KCN \rightarrow C_2H_5CN + KBr$Here,$C_2H_5Br$ (Ethyl bromide) reacts with $KCN$ to form $C_2H_5CN$ (Ethyl cyanide or Propanenitrile) as compound $A$.Further hydrolysis of $A$ $(C_2H_5CN)$ yields $B$ ($C_2H_5COOH$,Propanoic acid).Therefore,compound $A$ is Ethyl cyanide.

$C_2H_5Br$ $\xrightarrow{KCN} A$ $\xrightarrow{\text{Hydrolysis}} B$
The compound $A$ in the above reaction is

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$C_2H_5Br$ $\xrightarrow{KCN} A$ $\xrightarrow{\text{Hydrolysis}} B$The compound $A$ in the above reaction is