P_4O_{10} has short and long P-O bonds. The n | vedclass

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(D) The structure of $P_4O_{10}$ consists of a $P_4$ tetrahedron where each edge has an oxygen atom bridging the two phosphorus atoms ($P-O-P$ bonds).

Vedclass · Accepted Answer

$4$

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(D) The structure of $P_4O_{10}$ consists of a $P_4$ tetrahedron where each edge has an oxygen atom bridging the two phosphorus atoms ($P-O-P$ bonds). Additionally,each phosphorus atom is bonded to a terminal oxygen atom via a double bond $(P=O)$. There are $6$ bridging $P-O-P$ bonds and $4$ terminal $P=O$ bonds. The terminal $P=O$ bonds are shorter than the bridging $P-O$ bonds. Therefore,the number of short $(P=O)$ bonds is $4$.

$P_4O_{10}$ has short and long $P-O$ bonds. The number of short $(P=O)$ bonds in this compound is:

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