CH_3-C(=O)-OH xrightarrow{NaH^{14}CO_3} (A) ( | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) Both acetic acid $(CH_3COOH)$ and methanesulfonic acid $(CH_3SO_3H)$ are stronger acids than carbonic acid $(H_2CO_3)$. Therefore,they react with

Vedclass · Accepted Answer

$Ph-^{14}COOH$ and $Ph-^{14}COOH$

Vedclass · Answer

(C) Both acetic acid $(CH_3COOH)$ and methanesulfonic acid $(CH_3SO_3H)$ are stronger acids than carbonic acid $(H_2CO_3)$. Therefore,they react with $NaH^{14}CO_3$ to release $^{14}CO_2$ gas. Reaction $1$: $CH_3COOH + NaH^{14}CO_3 \rightarrow CH_3COONa + H_2O + ^{14}CO_2 \uparrow (A)$ Reaction $2$: $CH_3SO_3H + NaH^{14}CO_3 \rightarrow CH_3SO_3Na + H_2O + ^{14}CO_2 \uparrow (C)$ Both $(A)$ and $(C)$ are $^{14}CO_2$. When $^{14}CO_2$ reacts with Grignard reagent $(PhMgBr)$ followed by hydrolysis: $PhMgBr + ^{14}CO_2$ $\rightarrow Ph-^{14}COOMgBr$ $\xrightarrow{H_3O^{+}} Ph-^{14}COOH$ Thus,both $(B)$ and $(D)$ are $Ph-^{14}COOH$.

$CH_3-C(=O)-OH$ $\xrightarrow{NaH^{14}CO_3} (A) (\text{gas})$ $\xrightarrow[(ii) H_3O^{+}]{(i) PhMgBr} (B)$
$CH_3-S(=O)_2-OH$ $\xrightarrow{NaH^{14}CO_3} (C) (\text{gas})$ $\xrightarrow[(ii) H_3O^{+}]{(i) PhMgBr} (D)$
Product $(B)$ and $(D)$ in the above reaction are:

Similar Questions

The products $A$ and $B$ in the following reaction sequence are:

What is the correct order of acidic strength for the following compounds: $(a)$ Phenol,$(b)$ $p$-methylphenol,$(c)$ $p$-methylbenzoic acid,and $(d)$ Benzoic acid?

Arrange the following labelled hydrogens in decreasing order of acidity.

What is the major product of the above Friedel-Crafts reaction?

The product of the following reaction is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module

$CH_3-C(=O)-OH$ $\xrightarrow{NaH^{14}CO_3} (A) (\text{gas})$ $\xrightarrow[(ii) H_3O^{+}]{(i) PhMgBr} (B)$ $CH_3-S(=O)_2-OH$ $\xrightarrow{NaH^{14}CO_3} (C) (\text{gas})$ $\xrightarrow[(ii) H_3O^{+}]{(i) PhMgBr} (D)$ Product $(B)$ and $(D)$ in the above reaction are: