CH_3-CH(CH_3)-CH_2-CH_3 xrightarrow[hv]{Cl_2} | vedclass

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Question

(C) The reactant is $2$-methylbutane (isopentane). Monochlorination yields four structural isomers:$1.$ $Cl-CH_2-CH(CH_3)-CH_2-CH_3$ ($1$-chloro-$2$-m

Vedclass · Accepted Answer

$6$

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(C) The reactant is $2$-methylbutane (isopentane). Monochlorination yields four structural isomers:$1.$ $Cl-CH_2-CH(CH_3)-CH_2-CH_3$ ($1$-chloro-$2$-methylbutane): The $C2$ carbon is chiral,so it exists as a pair of enantiomers ($2$ stereoisomers).$2.$ $CH_3-CCl(CH_3)-CH_2-CH_3$ ($2$-chloro-$2$-methylbutane): This molecule is achiral,so it exists as $1$ stereoisomer.$3.$ $CH_3-CH(CH_3)-CHCl-CH_3$ ($2$-chloro-$3$-methylbutane): The $C3$ carbon is chiral,so it exists as a pair of enantiomers ($2$ stereoisomers).$4.$ $CH_3-CH(CH_3)-CH_2-CH_2-Cl$ ($1$-chloro-$3$-methylbutane): This molecule is achiral,so it exists as $1$ stereoisomer.Total number of monochloro products including stereoisomers = $2 + 1 + 2 + 1 = 6$.

$CH_3-CH(CH_3)-CH_2-CH_3 \xrightarrow[hv]{Cl_2} (x)$. Find the number of monochloro products including stereoisomers.

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