CH_3-CH(CH_3)-CH_3 + CH_2=CH_2 xrightarrow[2. | vedclass

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(C) The reaction of isobutane with ethene in the presence of $HF$ at low temperature is an alkylation reaction.$1$. The mechanism involves the formati

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$CH_3-C(CH_3)_2-CH_2-CH_3$

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(C) The reaction of isobutane with ethene in the presence of $HF$ at low temperature is an alkylation reaction.$1$. The mechanism involves the formation of a tert-butyl carbocation $(CH_3)_3C^+$ by the protonation of isobutane.$2$. This carbocation adds to the ethene molecule to form a new carbocation $(CH_3)_3C-CH_2-CH_2^+$.$3$. Through a series of rearrangements ($1$,$2$-hydride shift followed by $1,2-$methyl shift),a more stable carbocation is formed.$4$. Finally,hydride abstraction from another isobutane molecule yields the major product,$2$,$2$-dimethylbutane $(CH_3-C(CH_3)_2-CH_2-CH_3)$.

$CH_3-CH(CH_3)-CH_3 + CH_2=CH_2 \xrightarrow[2.5^oC]{HF} (A)$; $(A)$ is:

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