underset{text{symmetrical Ketone}}{(A)}, xrig | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The reaction sequence is as follows:$1$. $(A)$ is a symmetrical ketone. Reduction of a ketone with $LiAlH_{4}$ yields a secondary alcohol $(B)$.$2

Vedclass · Accepted Answer

$CH_{3}-CH_{2}-C(=O)-CH_{2}-CH_{3}$

Vedclass · Answer

(C) The reaction sequence is as follows:$1$. $(A)$ is a symmetrical ketone. Reduction of a ketone with $LiAlH_{4}$ yields a secondary alcohol $(B)$.$2$. Dehydration of the secondary alcohol $(B)$ in the presence of $H^{\oplus}$ and heat $(\Delta)$ produces an alkene.$3$. For the product to exhibit diastereomerism (specifically geometric isomerism),the alkene formed must have different groups attached to the double-bonded carbons.$4$. Let's analyze option $(C)$: $CH_{3}CH_{2}C(=O)CH_{2}CH_{3}$ (Pentan$-3-$one).$5$. $CH_{3}CH_{2}C(=O)CH_{2}CH_{3} \xrightarrow{LiAlH_{4}} CH_{3}CH_{2}CH(OH)CH_{2}CH_{3}$ (Pentan$-3-$ol).$6$. $CH_{3}CH_{2}CH(OH)CH_{2}CH_{3} \xrightarrow{H^{\oplus}, \Delta} CH_{3}CH=CHCH_{2}CH_{3}$ (Pent$-2-$ene).$7$. Pent$-2-$ene exists as cis and trans isomers,which are diastereomers.Therefore,the correct reactant $(A)$ is pentan$-3-$one.

List-$I$ (Reaction)	List-$II$ (Product)
$A$. $\text{Ketone} + NaBH_4$	$I$. $1^\circ$-alcohol
$B$. $\text{Ester} + LiAlH_4$	$II$. $3^\circ$-alcohol
$C$. $RMgX + \text{Ketone}$	$III$. $2^\circ$-alcohol
	$IV$. $\text{Alkane}$

$\underset{\text{symmetrical Ketone}}{(A)}\,$ $\xrightarrow{LiAlH_{4}}(B)$ $\xrightarrow[\Delta ]{H^{\oplus }}\text{Diastereomers}$
Reactant $(A)$ is

Similar Questions

In the reaction $CH_3CH_2OH \xrightarrow{OH^-} CH_3CHO$,which carbon atom undergoes oxidation?

What is the first intermediate formed during the reduction of carbonyl compounds by $H_2NNH_2$ and $KOH$?

$CCl_3CHO \xrightarrow[KOH]{Conc.}$ Main product is

Match the following reactions in List-$I$ with their products in List-$II$.
List-$I$ (Reaction) List-$II$ (Product)
$A$. $\text{Ketone} + NaBH_4$ $I$. $1^\circ$-alcohol
$B$. $\text{Ester} + LiAlH_4$ $II$. $3^\circ$-alcohol
$C$. $RMgX + \text{Ketone}$ $III$. $2^\circ$-alcohol
$IV$. $\text{Alkane}$

The product of the reaction is

Vedclass Test Series

Exam Paper Generator

Online Exam Module

$\underset{\text{symmetrical Ketone}}{(A)}\,$ $\xrightarrow{LiAlH_{4}}(B)$ $\xrightarrow[\Delta ]{H^{\oplus }}\text{Diastereomers}$Reactant $(A)$ is