Ph-CH=CH-CHO + CH_3-CH=CH-CHO xrightarrow[EtO | vedclass

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Question

(B) The reaction is a cross-aldol condensation between cinnamaldehyde $(Ph-CH=CH-CHO)$ and crotonaldehyde $(CH_3-CH=CH-CHO)$.In the presence of a base

Vedclass · Accepted Answer

$Ph-(CH=CH)_3-CHO$

Vedclass · Answer

(B) The reaction is a cross-aldol condensation between cinnamaldehyde $(Ph-CH=CH-CHO)$ and crotonaldehyde $(CH_3-CH=CH-CHO)$.In the presence of a base,the $\alpha$-hydrogen of crotonaldehyde is removed to form an enolate ion: $CH_2^--CH=CH-CHO$.This enolate ion attacks the carbonyl carbon of cinnamaldehyde.Following the aldol addition and subsequent dehydration upon heating $(\Delta)$,the final product is formed.The reaction sequence is:$CH_3-CH=CH-CHO \xrightarrow{	ext{base}} CH_2^--CH=CH-CHO$$CH_2^--CH=CH-CHO + Ph-CH=CH-CHO ightarrow Ph-CH=CH-CH(OH)-CH_2-CH=CH-CHO$$Ph-CH=CH-CH(OH)-CH_2-CH=CH-CHO \xrightarrow{\Delta, -H_2O} Ph-(CH=CH)_3-CHO$The final product is $Ph-(CH=CH)_3-CHO$.

$Ph-CH=CH-CHO + CH_3-CH=CH-CHO \xrightarrow[EtOH, \Delta]{\text{base}} (A) (87\%)$; The product of this reaction is:

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