The major product Q of the following reaction | vedclass

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(D) Step $1$: Conversion of toluene to $(P)$. Toluene reacts with $KMnO_4 / KOH$ followed by $H_3O^+$ to form $p$-methylbenzoic acid. This acid then r

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(D) Step $1$: Conversion of toluene to $(P)$. Toluene reacts with $KMnO_4 / KOH$ followed by $H_3O^+$ to form $p$-methylbenzoic acid. This acid then reacts with $PCl_5$ to form $p$-methylbenzoyl chloride,which is $(P)$.Step $2$: Conversion of bromobenzene to $(Q)$. Bromobenzene reacts with $Mg$ to form phenylmagnesium bromide,which then reacts with $CdCl_2$ to form diphenylcadmium. This organocadmium compound reacts with $(P)$ ($p$-methylbenzoyl chloride) to form the final product $(Q)$,which is $4$-methylbenzophenone.

The major product $Q$ of the following reaction scheme is:

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