CH_3CH=CHCHO xrightarrow[text{Aldol condensat | vedclass

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Question

(A) The reaction is an aldol condensation of crotonaldehyde $(CH_3CH=CHCHO)$.In the presence of a base $(OH^-)$,two molecules of crotonaldehyde underg

Vedclass · Accepted Answer

$CH_3(CH=CH)_3CHO$

Vedclass · Answer

(A) The reaction is an aldol condensation of crotonaldehyde $(CH_3CH=CHCHO)$.In the presence of a base $(OH^-)$,two molecules of crotonaldehyde undergo aldol condensation to form a $\beta$-hydroxy aldehyde.Upon heating $(\Delta)$,this intermediate undergoes dehydration (loss of $H_2O$) to form an $\alpha,\beta$-unsaturated aldehyde.The reaction is: $CH_3CH=CHCHO + CH_3CH=CHCHO \rightarrow CH_3CH=CH-CH(OH)-CH_2-CH=CHCHO$ (intermediate).Dehydration gives: $CH_3CH=CH-CH=CH-CH=CHCHO$.This corresponds to $CH_3(CH=CH)_3CHO$.

$CH_3CH=CHCHO$ $\xrightarrow[\text{Aldol condensation}]{OH^{-}}$ $\xrightarrow{\Delta} A$; Product $A$ is

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