K_2HgI_4 is 40 % ionized in aqueous solution. | vedclass

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(B) The dissociation of $K_2[HgI_4]$ is given by: $K_2[HgI_4] \rightleftharpoons 2K^{+} + [HgI_4]^{2-}$ The number of ions produced per formula unit i

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$1.8$

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(B) The dissociation of $K_2[HgI_4]$ is given by: $K_2[HgI_4] ightleftharpoons 2K^{+} + [HgI_4]^{2-}$ The number of ions produced per formula unit is $n = 3$ ($2K^{+}$ and $1[HgI_4]^{2-}$). The degree of ionization is $\alpha = 40 \% = 0.4$. The van't Hoff factor $(i)$ is calculated using the formula: $i = 1 + (n - 1)\alpha$. Substituting the values: $i = 1 + (3 - 1) 	imes 0.4$. $i = 1 + 2 	imes 0.4 = 1 + 0.8 = 1.8$.

$K_2HgI_4$ is $40 \%$ ionized in aqueous solution. The value of its van't Hoff factor $(i)$ is:

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