(A) The $XeF_2$ molecule has a central $Xe$ atom with $8$ valence electrons. It forms $2$ bonds with $F$ atoms and has $3$ lone pairs of electrons. Th

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

(A) The $XeF_2$ molecule has a central $Xe$ atom with $8$ valence electrons. It forms $2$ bonds with $F$ atoms and has $3$ lone pairs of electrons. The total number of electron pairs is $5$,which corresponds to $sp^3d$ hybridization. According to $VSEPR$ theory,the $3$ lone pairs occupy the equatorial positions to minimize repulsion,resulting in a linear geometry.