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(A) The number of lone pairs on the central atoms are calculated as follows:$1$. In $H_{2}O$, Oxygen has $6$ valence electrons, $2$ are used in bondin

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$2, 1, 1, 3$

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(A) The number of lone pairs on the central atoms are calculated as follows:$1$. In $H_{2}O$, Oxygen has $6$ valence electrons, $2$ are used in bonding with $H$, leaving $4$ electrons or $2$ lone pairs.$2$. In $SnCl_{2}$, Tin $(Sn)$ has $4$ valence electrons, $2$ are used in bonding with $Cl$, leaving $2$ electrons or $1$ lone pair.$3$. In $PCl_{3}$, Phosphorus $(P)$ has $5$ valence electrons, $3$ are used in bonding with $Cl$, leaving $2$ electrons or $1$ lone pair.$4$. In $XeF_{2}$, Xenon $(Xe)$ has $8$ valence electrons, $2$ are used in bonding with $F$, leaving $6$ electrons or $3$ lone pairs.Thus, the number of lone pairs are $2, 1, 1$ and $3$ respectively.

List-$I$	List-$II$
$(A)$ $PCl_3$	$(I)$ Square planar
$(B)$ $BF_3$	$(II)$ $T$-shape
$(C)$ $ClF_3$	$(III)$ Trigonal pyramidal
$(D)$ $XeF_4$	$(IV)$ See-saw
	$(V)$ Trigonal planar

The number of lone pairs of electrons on the central atoms of $H_{2}O, SnCl_{2}, PCl_{3}$ and $XeF_{2}$ respectively, are

Similar Questions

Draw the structure of chlorous acid $(HClO_2)$.

Which of the following is not a correct statement?

Match the molecules in List-$I$ with their correct geometries in List-$II$ according to $VSEPR$ theory:
List-$I$ List-$II$
$(A)$ $PCl_3$ $(I)$ Square planar
$(B)$ $BF_3$ $(II)$ $T$-shape
$(C)$ $ClF_3$ $(III)$ Trigonal pyramidal
$(D)$ $XeF_4$ $(IV)$ See-saw
$(V)$ Trigonal planar

Which of the following molecules has trigonal planar geometry?

Identify the pair of species with same geometries.

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