1000 , mL of 1 , M CuSO_{4(aq)} is electrolys | vedclass

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Question

(C) The electrolysis of $CuSO_{4(aq)}$ using $Pt$ electrodes involves the reduction of $Cu^{2+}$ ions at the cathode $(Cu^{2+} + 2e^- \rightarrow Cu)$

Vedclass · Accepted Answer

$pH$ of the solution is $8$ after electrolysis

Vedclass · Answer

(C) The electrolysis of $CuSO_{4(aq)}$ using $Pt$ electrodes involves the reduction of $Cu^{2+}$ ions at the cathode $(Cu^{2+} + 2e^- \rightarrow Cu)$ and the oxidation of $H_2O$ at the anode $(2H_2O \rightarrow O_2 + 4H^+ + 4e^-)$.As $Cu^{2+}$ ions are removed from the solution,the blue colour intensity decreases.If $Cu$ electrodes were used,$Cu$ would dissolve at the anode at the same rate it deposits at the cathode,keeping the concentration of $Cu^{2+}$ constant.The production of $H^+$ ions at the anode makes the solution acidic,so the $pH$ will be less than $7$.Therefore,the statement that the $pH$ is $8$ is incorrect.

$1000 \, mL$ of $1 \, M$ $CuSO_{4(aq)}$ is electrolysed by $9.65 \, A$ current for $100 \, s$ using $Pt$ electrodes. Which statement is incorrect?

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