The standard reduction potentials of 2H^{+}/H | vedclass

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(B) substance with a lower (more negative) standard reduction potential acts as a stronger reducing agent. Conversely,a substance with a higher (more

Vedclass · Accepted Answer

$I, II, III$

Vedclass · Answer

(B) substance with a lower (more negative) standard reduction potential acts as a stronger reducing agent. Conversely,a substance with a higher (more positive) standard reduction potential acts as a stronger oxidizing agent.$Zn^{2+}/Zn$$-0.76 \ V$$2H^{+}/H_2$$0.00 \ V$$Cu^{2+}/Cu$$0.34 \ V$$NO_3^{-}, H^{+}/NO$$0.97 \ V$$I.$ Since $E^{\circ}_{Cu^{2+}/Cu} (0.34 \ V) > E^{\circ}_{2H^{+}/H_2} (0.0 \ V)$,$H^{+}$ cannot oxidize $Cu$ to $Cu^{2+}$. Statement $I$ is correct.$II.$ Since $E^{\circ}_{Zn^{2+}/Zn} (-0.76 \ V) $III.$ Since $E^{\circ}_{NO_3^{-}, H^{+}/NO} (0.97 \ V) > E^{\circ}_{Cu^{2+}/Cu} (0.34 \ V)$,$NO_3^{-}$ can oxidize $Cu$ to $Cu^{2+}$. Statement $III$ is correct.Therefore,all statements $I, II,$ and $III$ are correct.

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