In the given reaction,what is $y$?
$CH_3CH_2COCH_2COOH$ $\xrightarrow{\Delta} x$ $\xrightarrow[(ii) H_2O]{(i) LiAlH_4} y$

The reaction shown below is:

Reactant of Column-$I$ when reacted with acetaldehyde in the presence of $H^{+}$ gives the product given in Column-$II$ and their names are given in Column-$III$. Match the reactants in Column-$I$ with the products in Column-$II$ and their names in Column-$III$.

Column-$I$ (Reagent)	Column-$II$ (Product) and Column-$III$ (Name)
$A$. Ammonia $(NH_{3})$	$i$. $CH_{3}CH=NCH_{3}$; $m$. Acetaldehyde hydrazone
$B$. Amine $(CH_{3}NH_{2})$	$ii$. $CH_{3}CH=NNH_{2}$; $n$. Acetaldehyde oxime
$C$. Hydroxyl amine $(NH_{2}OH)$	$iii$. $CH_{3}CH=NH$; $o$. Acetaldehyde imine
$D$. Hydrazine $(NH_{2}NH_{2})$	$iv$. $CH_{3}CH=NOH$; $q$. Acetaldehyde methyl imine

In the given Cannizzaro reaction,the slowest step is:
$2PhCHO \xrightarrow{KOH} PhCH_2OH + PhCOO^-$

$CH_3-CHO$ $\xrightarrow{HCN} (A)$ $\xrightarrow{H_3O^{+}} (B)$ $\xrightarrow{\Delta} (C)$ $\xrightarrow{LiAlH_4} (D)$ $\xrightarrow{HIO_4} HCHO + (E)$. Compound $(C)$ can show geometrical isomerism. Product $(E)$ of the reaction will be:

Identify the product of the following reaction: $Formaldehyde + Benzaldehyde \xrightarrow[H_3O^{+}]{conc. NaOH} \text{product}$