Identify the product of the following reactio | vedclass

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Question

(C) The reaction between $Formaldehyde$ $(HCHO)$ and $Benzaldehyde$ $(C_6H_5CHO)$ in the presence of concentrated $NaOH$ is a $Cross-Cannizzaro$ react

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Methanoic acid and phenyl methanol

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(C) The reaction between $Formaldehyde$ $(HCHO)$ and $Benzaldehyde$ $(C_6H_5CHO)$ in the presence of concentrated $NaOH$ is a $Cross-Cannizzaro$ reaction. Since $Formaldehyde$ has no $\alpha$-hydrogen,it is more susceptible to nucleophilic attack by $OH^-$. $Formaldehyde$ undergoes oxidation to form $Methanoic$ $acid$ (which exists as $Sodium$ $formate$ in basic medium) and $Benzaldehyde$ undergoes reduction to form $Phenyl$ $methanol$ ($Benzyl$ $alcohol$). Upon acidification with $H_3O^+$,$Sodium$ $formate$ converts to $Methanoic$ $acid$ $(HCOOH)$. Thus,the products are $Methanoic$ $acid$ and $Phenyl$ $methanol$.

Identify the product of the following reaction: $Formaldehyde + Benzaldehyde \xrightarrow[H_3O^{+}]{conc. NaOH} \text{product}$

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