Na_2B_4O_7 cdot 10H_2O xrightarrow{text{Heat} | vedclass

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(C) The thermal decomposition of borax $(Na_2B_4O_7 \cdot 10H_2O)$ produces sodium metaborate $(NaBO_2)$ and boric anhydride $(B_2O_3)$: $Na_2B_4O_7 \

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$B_2O_3$ and $Cr(BO_2)_3$

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(C) The thermal decomposition of borax $(Na_2B_4O_7 \cdot 10H_2O)$ produces sodium metaborate $(NaBO_2)$ and boric anhydride $(B_2O_3)$: $Na_2B_4O_7 \cdot 10H_2O \xrightarrow{	ext{Heat}} 2NaBO_2 + B_2O_3 + 10H_2O$. Thus,$X$ is $B_2O_3$. When $B_2O_3$ reacts with $Cr_2O_3$ upon heating,it forms chromium$(III)$ metaborate $(Cr(BO_2)_3)$,which is a green-colored bead: $Cr_2O_3 + 3B_2O_3 \xrightarrow{	ext{Heat}} 2Cr(BO_2)_3$. Thus,$Y$ is $Cr(BO_2)_3$.

$Na_2B_4O_7 \cdot 10H_2O \xrightarrow{\text{Heat}} X + NaBO_2 + H_2O$,$X + Cr_2O_3 \xrightarrow{\text{Heat}} \underset{(\text{Green coloured})}{Y}$. $X$ and $Y$ are

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