H_3BO_3 xrightarrow{T_1} X xrightarrow{T_2} Y | vedclass

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(A) The thermal decomposition of orthoboric acid $(H_3BO_3)$ occurs in steps:$1$. $H_3BO_3 \xrightarrow{100^{\circ} C} HBO_2 (	ext{Metaboric acid}) +

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$X = 	ext{Metaboric acid}, Y = 	ext{Tetraboric acid}$

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(A) The thermal decomposition of orthoboric acid $(H_3BO_3)$ occurs in steps:$1$. $H_3BO_3 \xrightarrow{100^{\circ} C} HBO_2 (	ext{Metaboric acid}) + H_2O$$2$. $4HBO_2 \xrightarrow{160^{\circ} C} H_2B_4O_7 (	ext{Tetraboric acid}) + H_2O$$3$. $H_2B_4O_7 \xrightarrow{	ext{red hot}} 2B_2O_3 + H_2O$Given $T_1 < T_2$,$X$ is $HBO_2$ (metaboric acid) and $Y$ is $H_2B_4O_7$ (tetraboric acid).

$H_3BO_3$ $\xrightarrow{T_1} X$ $\xrightarrow{T_2} Y$ $\xrightarrow{\text{red hot}} B_2O_3$
If $T_1 < T_2$,then $X$ and $Y$ respectively are:

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$H_3BO_3$ $\xrightarrow{T_1} X$ $\xrightarrow{T_2} Y$ $\xrightarrow{\text{red hot}} B_2O_3$If $T_1 < T_2$,then $X$ and $Y$ respectively are: