${}_{24}Cr$ has configuration $3d^5\,4s^1$ instead of $3d^4\,4s^2$ because of

  • A
    Higher exchange energy
  • B
    Symmetrical distribution of electron
  • C
    $A$ and $B$ both
  • D
    None of these

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An electron has principal quantum number $n = 3$. The number of its $(i)$ sub-shells and $(ii)$ orbitals would be respectively:

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The rule which states that an electron enters the sub-shell for which the $(n + l)$ value is minimum is known as:

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