50 , g of copper is heated to increase its te | vedclass

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Question

(A) The heat absorbed by a substance is given by the formula: $Q = m \cdot c \cdot \Delta T$.First,calculate the heat absorbed by copper:$m_{Cu} = 50

Vedclass · Accepted Answer

$5$

Vedclass · Answer

(A) The heat absorbed by a substance is given by the formula: $Q = m \cdot c \cdot \Delta T$.First,calculate the heat absorbed by copper:$m_{Cu} = 50 \, g = 0.05 \, kg$$c_{Cu} = 420 \, J \, kg^{-1} \, ^\circ C^{-1}$$\Delta T_{Cu} = 10 \, ^\circ C$$Q = 0.05 	imes 420 	imes 10 = 210 \, J$.Now,apply the same heat to water:$m_{w} = 10 \, g = 0.01 \, kg$$c_{w} = 4200 \, J \, kg^{-1} \, ^\circ C^{-1}$$Q = m_{w} \cdot c_{w} \cdot \Delta T_{w}$$210 = 0.01 	imes 4200 	imes \Delta T_{w}$$210 = 42 	imes \Delta T_{w}$$\Delta T_{w} = \frac{210}{42} = 5 \, ^\circ C$.

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