(C) $Na_2O_2$ is a strong oxidizing agent. It oxidizes $SO_3^{2-}$ to $SO_4^{2-}$.Given the reaction: $Na_2SO_3(aq.) + Na_2O_2(aq.) \to Na_2SO_4(aq.)

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

(C) $Na_2O_2$ is a strong oxidizing agent. It oxidizes $SO_3^{2-}$ to $SO_4^{2-}$.Given the reaction: $Na_2SO_3(aq.) + Na_2O_2(aq.) \to Na_2SO_4(aq.) + Na_2O(aq.)$.Here,$X = Na_2SO_3$ and $Y = Na_2SO_4$.When $Y$ $(Na_2SO_4)$ reacts with $BaCl_2$,it forms $BaSO_4$ $(Z)$,which is a white precipitate insoluble in dilute $HCl$.Therefore,the anion present in salt $X$ is $SO_3^{2-}$.

Class 11 Chemistry Redox Reactions Mix Examples-Redox Reactions

Medium

$X(aq.) + Na_2O_2 \to Y(aq.) \xrightarrow{BaCl_2} Z \downarrow_{\text{Insoluble in dil. } HCl}$
$X$ and $Y$ are different sodium salts. Then the anion present in the salt $(X)$ is:

A
$Cr_2O_7^{2-}$
B
$C_2O_4^{2-}$
C
$SO_3^{2-}$
D
$SO_4^{2-}$

Explore More

Browse All

Question Bank

All Subjects

Class 11 Questions

Class 11

Chemistry Questions

Chapter

Redox Reactions

Subtopic

Mix Examples-Redox Reactions

What is the equivalent weight of the reductant in the reaction $2[Fe(CN)_6]^{3-} + H_2O_2 + 2OH^{-} \rightarrow 2[Fe(CN)_6]^{4-} + 2H_2O + O_2$? (Given: $Fe = 56, C = 12, N = 14, O = 16, H = 1$)

Medium

View Solution

$2 \text{ mol}$ of $FeSO_4$ are oxidized by $X \text{ mol}$ of $KMnO_4$ whereas $2 \text{ mol}$ of $FeC_2O_4$ are oxidized by $Y \text{ mol}$ of $KMnO_4$. The ratio of $X$ and $Y$ is:

Difficult

View Solution

Consider the following list of reagents:
Acidified $K_2Cr_2O_7$,alkaline $KMnO_4$,$CuSO_4$,$H_2O_2$,$Cl_2$,$O_3$,$FeCl_3$,$HNO_3$ and $Na_2S_2O_3$. The total number of reagents that can oxidise aqueous iodide to iodine is

MediumIIT 2014

View Solution

Acidified $KMnO_4$ is decolourised by:

Easy

View Solution

Blue colouration is not produced when :

Difficult

View Solution

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial

For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free

For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo

$X(aq.) + Na_2O_2 \to Y(aq.) \xrightarrow{BaCl_2} Z \downarrow_{\text{Insoluble in dil. } HCl}$$X$ and $Y$ are different sodium salts. Then the anion present in the salt $(X)$ is:

Similar Questions

What is the equivalent weight of the reductant in the reaction $2[Fe(CN)_6]^{3-} + H_2O_2 + 2OH^{-} \rightarrow 2[Fe(CN)_6]^{4-} + 2H_2O + O_2$? (Given: $Fe = 56, C = 12, N = 14, O = 16, H = 1$)

$2 \text{ mol}$ of $FeSO_4$ are oxidized by $X \text{ mol}$ of $KMnO_4$ whereas $2 \text{ mol}$ of $FeC_2O_4$ are oxidized by $Y \text{ mol}$ of $KMnO_4$. The ratio of $X$ and $Y$ is:

Consider the following list of reagents:Acidified $K_2Cr_2O_7$,alkaline $KMnO_4$,$CuSO_4$,$H_2O_2$,$Cl_2$,$O_3$,$FeCl_3$,$HNO_3$ and $Na_2S_2O_3$. The total number of reagents that can oxidise aqueous iodide to iodine is

Acidified $KMnO_4$ is decolourised by:

Blue colouration is not produced when :

Vedclass Test Series

Exam Paper Generator

Online Exam Module

$X(aq.) + Na_2O_2 \to Y(aq.) \xrightarrow{BaCl_2} Z \downarrow_{\text{Insoluble in dil. } HCl}$
$X$ and $Y$ are different sodium salts. Then the anion present in the salt $(X)$ is:

Consider the following list of reagents:
Acidified $K_2Cr_2O_7$,alkaline $KMnO_4$,$CuSO_4$,$H_2O_2$,$Cl_2$,$O_3$,$FeCl_3$,$HNO_3$ and $Na_2S_2O_3$. The total number of reagents that can oxidise aqueous iodide to iodine is