Blue colouration is not produced when :

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(C) Let us analyze each reaction:$1$. $Cr_2O_7^{2-} + H_2O_2 + H^{+} \rightarrow CrO_5 + H_2O$. $CrO_5$ is a deep blue coloured compound.$2$. $NO_2 +

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$Fe^{3+} + SCN^{-} \xrightarrow{}$

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(C) Let us analyze each reaction:$1$. $Cr_2O_7^{2-} + H_2O_2 + H^{+} \rightarrow CrO_5 + H_2O$. $CrO_5$ is a deep blue coloured compound.$2$. $NO_2 + NO \xrightarrow{-23^{\circ}C} N_2O_3$. $N_2O_3$ is a blue solid at low temperatures.$3$. $Fe^{3+} + SCN^{-} \rightarrow [Fe(SCN)]^{2+}$. This complex is blood-red in colour,not blue.$4$. $CuSO_{4(s)} + 5H_2O_{(g)} \rightarrow CuSO_4 \cdot 5H_2O_{(s)}$. Hydrated copper$(II)$ sulfate is blue.Therefore,the reaction that does not produce a blue colour is $Fe^{3+} + SCN^{-} \rightarrow [Fe(SCN)]^{2+}$.

Column-$I$ [Type of reaction]	Column-$II$ [Example]
$I$. Intermolecular redox reaction	$A$. $CH_4 + 2O_2 \rightarrow CO_2 + 2H_2O$
$II$. Intramolecular redox reaction	$B$. $NH_4NO_2 \rightarrow N_2 + 2H_2O$
$III$. Disproportionation reaction	$C$. $2H_2O_2 \rightarrow 2H_2O + O_2$
$IV$. Comproportionation reaction	$D$. $KClO_3 \rightarrow KCl + \frac{3}{2}O_2$

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