At the same temperature,which of the followin | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The root mean square speed $(u_{rms})$ of a gas is given by the formula: $u_{rms} = \sqrt{\frac{3RT}{M}}$,where $R$ is the universal gas constant,

Vedclass · Accepted Answer

$H_2$

Vedclass · Answer

(D) The root mean square speed $(u_{rms})$ of a gas is given by the formula: $u_{rms} = \sqrt{\frac{3RT}{M}}$,where $R$ is the universal gas constant,$T$ is the temperature,and $M$ is the molar mass of the gas.Since $R$ and $T$ are constant,$u_{rms} \propto \frac{1}{\sqrt{M}}$.This means the gas with the lowest molar mass will have the highest root mean square speed.The molar masses are: $M(SO_2) = 64 \ g/mol$,$M(CO_2) = 44 \ g/mol$,$M(O_2) = 32 \ g/mol$,and $M(H_2) = 2 \ g/mol$.Since $H_2$ has the lowest molar mass,it will have the highest $u_{rms}$.

At the same temperature,which of the following gases will have the highest root mean square speed?

Similar Questions

$\alpha, v$ and $u$ represent the most probable velocity, average velocity, and root mean square velocity, respectively, of a gas at a particular temperature. The correct order among the following is:

Which of the following pairs will diffuse at the same rate through a porous plug?

The rms velocity of oxygen molecules at $27^{\circ} C$ is around $800 \ m/s$. The rms velocity of methane molecules at $600 \ K$ temperature is around ...... (in $m/s$)

At $STP$,write the order of root mean square speed $(u_{rms})$ for the molecules $H_2, N_2, O_2$,and $HBr$.

The ratio of the root mean square velocity of $H_2$ at $50 \ K$ to that of $O_2$ at $800 \ K$ is .......

Vedclass Test Series

Exam Paper Generator

Online Exam Module