In a $H$ atom,if the angular momentum of an electron is $3.164 \times 10^{-34} \ kg \ m^2 \ s^{-1}$,what is the energy of the electron in that orbit in $eV$?

In the Balmer series of the hydrogen atom spectrum,which electronic transition causes the third line?

When the electron of a hydrogen atom returns to the $L$ shell $(n=2)$ from shells of higher energy,we get a series of lines in the spectrum. This series is called:

Observe the following statements:
Statement-$I$: Rutherford model of an atom cannot explain the stability of an atom.
Statement-$II$: The wavelength of $X$-rays is higher than the wavelength of microwaves.
The correct answer is:

The separation energy of the electron present in the shell $n = 3$ is $1.51 \ eV$. What is the energy in the first excited state? ............ $eV$

Calculate the wavenumber of the photon emitted during transition from the orbit of $n=2$ to $n=1$ in a hydrogen atom. $[R_H = 109677 \ cm^{-1}]$ (in $cm^{-1}$)