The separation energy of the electron present | vedclass

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(B) $1$st excited state corresponds to $n = 2$.The energy of an electron in a hydrogen-like atom is given by $E_n = -13.6 	imes \frac{Z^2}{n^2} \ eV$

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$-3.4$

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(B) $1$st excited state corresponds to $n = 2$.The energy of an electron in a hydrogen-like atom is given by $E_n = -13.6 	imes \frac{Z^2}{n^2} \ eV$.For $n = 3$,the energy is $E_3 = -1.51 \ eV$.For $n = 2$,the energy is $E_2 = -13.6 	imes \frac{Z^2}{2^2} = -13.6 	imes \frac{Z^2}{4}$.Since $E_3 = -13.6 	imes \frac{Z^2}{9} = -1.51 \ eV$,we have $-13.6 	imes Z^2 = -1.51 	imes 9 = -13.59 \approx -13.6$.Thus,$E_2 = \frac{-13.6}{4} = -3.4 \ eV$.

The separation energy of the electron present in the shell $n = 3$ is $1.51 \ eV$. What is the energy in the first excited state? ............ $eV$

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