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(B) The energy of an orbital is determined by the $(n + l)$ rule.For $5p$: $n=5, l=1$,so $(n + l) = 6$.For $4f$: $n=4, l=3$,so $(n + l) = 7$.For $6s$:

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$5p < 6s < 4f < 5d$

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(B) The energy of an orbital is determined by the $(n + l)$ rule.For $5p$: $n=5, l=1$,so $(n + l) = 6$.For $4f$: $n=4, l=3$,so $(n + l) = 7$.For $6s$: $n=6, l=0$,so $(n + l) = 6$.For $5d$: $n=5, l=2$,so $(n + l) = 7$.Comparing $(n + l)$ values,$5p$ and $6s$ have the same value $(6)$,and $4f$ and $5d$ have the same value $(7)$.When $(n + l)$ values are equal,the orbital with the lower $n$ value has lower energy.Thus,$5p Combining these,the order is $5p < 6s < 4f < 5d$.

Which of the following represents the correct order of energy for the orbitals?

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