68 , ^circ F = ........ , K. | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The relationship between Fahrenheit and Celsius is given by: $^\circ F = \frac{9}{5} ( ^\circ C ) + 32$. Substituting $68 \, ^\circ F$: $68 = \fra

Vedclass · Accepted Answer

$293$

Vedclass · Answer

(C) The relationship between Fahrenheit and Celsius is given by: $^\circ F = \frac{9}{5} ( ^\circ C ) + 32$. Substituting $68 \, ^\circ F$: $68 = \frac{9}{5} ( ^\circ C ) + 32$. $68 - 32 = \frac{9}{5} ( ^\circ C ) \implies 36 = \frac{9}{5} ( ^\circ C )$. $^\circ C = \frac{36 	imes 5}{9} = 20 \, ^\circ C$. To convert Celsius to Kelvin: $K = ^\circ C + 273.15$. $K = 20 + 273 = 293 \, K$ (using $273$ as the standard conversion factor).

$68 \, ^\circ F = ........ \, K.$

Similar Questions

Express the following in scientific notation:
$(i)$ $0.0048$
$(ii)$ $234,000$
$(iii)$ $8008$
$(iv)$ $500.0$
$(v)$ $6.0012$

From the following masses,the one which is expressed nearest to the milligram is (in $g$)

$0.15 \, \mathring{A} = \dots \, \text{nm}$

Which smaller units of $kg$ are used to measure the mass of chemicals with very low mass?

In the equation of state of an ideal gas $PV = nRT$,the value of the universal gas constant $R$ depends only on:

Vedclass Test Series

Exam Paper Generator

Online Exam Module