In how many grams of CO_2 is the number of C | vedclass

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(D) The number of moles of $C$ atoms is given by $n = \frac{1.3699 	imes 10^{23}}{6.022 	imes 10^{23}} = 0.2275 \ mol$.Since one molecule of $CO_2$

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$10$

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(D) The number of moles of $C$ atoms is given by $n = \frac{1.3699 	imes 10^{23}}{6.022 	imes 10^{23}} = 0.2275 \ mol$.Since one molecule of $CO_2$ contains one $C$ atom,the moles of $CO_2$ are equal to the moles of $C$ atoms,which is $0.2275 \ mol$.The molar mass of $CO_2$ is $44 \ g/mol$.Mass of $CO_2 = 	ext{moles} 	imes 	ext{molar mass} = 0.2275 \ mol 	imes 44 \ g/mol = 10 \ g$.

In how many grams of $CO_2$ is the number of $C$ atoms equal to $1.3699 \times 10^{23}$?

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