Calculate the mass of Ca in g present in Ca(N | vedclass

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(D) The molar mass of $Ca(NO_3)_2$ is $40 + 2 	imes (14 + 3 	imes 16) = 40 + 2 	imes 62 = 164 \ g/mol$. In one mole of $Ca(NO_3)_2$,there are $2$ m

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$28.57$

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(D) The molar mass of $Ca(NO_3)_2$ is $40 + 2 	imes (14 + 3 	imes 16) = 40 + 2 	imes 62 = 164 \ g/mol$. In one mole of $Ca(NO_3)_2$,there are $2$ moles of nitrogen atoms $(2 	imes 14 = 28 \ g)$ and $1$ mole of calcium $(40 \ g)$. Using the unitary method: $28 \ g$ of nitrogen corresponds to $40 \ g$ of calcium. Therefore,$20 \ g$ of nitrogen corresponds to $\frac{20 	imes 40}{28} \ g$ of calcium. Mass of $Ca = \frac{800}{28} = \frac{200}{7} \approx 28.57 \ g$.

Calculate the mass of $Ca$ in $g$ present in $Ca(NO_3)_2$ that contains $20 \ g$ of nitrogen.

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