According to the reaction 2A + B to C,8 mol | vedclass

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(C) The balanced chemical equation is $2A + B 	o C$.For $2 \ mol$ of $A$,$1 \ mol$ of $B$ is required.For $8 \ mol$ of $A$,the required amount of $B$

Vedclass · Accepted Answer

$4$

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(C) The balanced chemical equation is $2A + B 	o C$.For $2 \ mol$ of $A$,$1 \ mol$ of $B$ is required.For $8 \ mol$ of $A$,the required amount of $B$ is $(8 / 2) 	imes 1 = 4 \ mol$.Since we have $5 \ mol$ of $B$ available,$B$ is in excess and $A$ is the limiting reagent.The amount of product $C$ formed depends on the limiting reagent $A$.According to the stoichiometry,$2 \ mol$ of $A$ produces $1 \ mol$ of $C$.Therefore,$8 \ mol$ of $A$ will produce $(8 / 2) 	imes 1 = 4 \ mol$ of $C$.

According to the reaction $2A + B \to C$,$8 \ mol$ of $A$ and $5 \ mol$ of $B$ will produce how many moles of $C$?

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