What is the mass of glucose in 500 g of an a | vedclass

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(D) Molality $(m)$ is defined as the number of moles of solute per kilogram of solvent.Let the mass of glucose be $W \ g$.The molar mass of glucose $(

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$41.3$

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(D) Molality $(m)$ is defined as the number of moles of solute per kilogram of solvent.Let the mass of glucose be $W \ g$.The molar mass of glucose $(C_6H_{12}O_6)$ is $180 \ g/mol$.The mass of the solvent (water) is $(500 - W) \ g$.Using the formula: $m = \frac{W 	imes 1000}{M_m 	imes W_{solvent}}$$0.5 = \frac{W 	imes 1000}{180 	imes (500 - W)}$$0.5 	imes 180 	imes (500 - W) = 1000 	imes W$$90 	imes (500 - W) = 1000 	imes W$$45000 - 90 	imes W = 1000 	imes W$$1090 	imes W = 45000$$W = \frac{45000}{1090} \approx 41.28 \ g \approx 41.3 \ g$.

What is the mass of glucose in $500 \ g$ of an aqueous solution of glucose having a molality of $0.5 \ m$?

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