How many millimoles of H^{+} ions are present | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The normality $(N)$ of a solution is given by $N = M 	imes 	ext{n-factor}$.For $H_3PO_4$,the n-factor is $3$ (as it is a tribasic acid).Therefor

Vedclass · Accepted Answer

$60$

Vedclass · Answer

(C) The normality $(N)$ of a solution is given by $N = M 	imes 	ext{n-factor}$.For $H_3PO_4$,the n-factor is $3$ (as it is a tribasic acid).Therefore,the molarity $(M)$ is $M = \frac{N}{3} = \frac{0.6}{3} = 0.2 \, M$.Millimoles of $H_3PO_4 = 	ext{Molarity} 	imes 	ext{Volume in } mL = 0.2 	imes 100 = 20 \, mmol$.Since $1 \, mol$ of $H_3PO_4$ dissociates to give $3 \, mol$ of $H^{+}$ ions,$1 \, mmol$ of $H_3PO_4$ gives $3 \, mmol$ of $H^{+}$ ions.Millimoles of $H^{+} = 3 	imes 20 = 60 \, mmol$.

How many millimoles of $H^{+}$ ions are present in $100 \, mL$ of $0.6 \, N \, H_3PO_4$?

Similar Questions

The volume of $O_2$ required for the complete combustion of $5$ moles of propane $(C_3H_8)$ at $25$ $^\circ C$ is ............... liters.

$29.2 \% (w/w)$ $HCl$ stock solution has a density of $1.25 \ g \ mL^{-1}$. The molecular weight of $HCl$ is $36.5 \ g \ mol^{-1}$. The volume $(mL)$ of stock solution required to prepare a $200 \ mL$ solution of $0.4 \ M$ $HCl$ is :

At $27\,^oC$,for the reaction,$N_2O_{4(g)} \to 2NO_{2(g)}$,the rate of reaction is $6 \times 10^{-3} \, atm \, min^{-1}$. Find the rate of the same reaction in terms of $mol \, L^{-1} \, min^{-1}$.

How many moles of $KCl$ are dissolved in $1000 \ mL$ of $3 \ M$ $KCl$ solution?

What is the percentage atom economy when the formula weight of the product obtained is $70 \ u$ and the sum of the formula weights of the reactants is $140 \ u$ (in $\%$)?

Vedclass Test Series

Exam Paper Generator

Online Exam Module