If the dipole moment of Images-1 is 1.5 D,th | vedclass

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(C) The dipole moment of chlorobenzene $(Images-1)$ is given as $1.5 \ D$.In $Images-2$ ($1$,$2$,$3$-trichlorobenzene),the molecule has three $C-Cl$ b

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$3$

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(C) The dipole moment of chlorobenzene $(Images-1)$ is given as $1.5 \ D$.In $Images-2$ ($1$,$2$,$3$-trichlorobenzene),the molecule has three $C-Cl$ bonds.The dipole moment of $1,2,3-$trichlorobenzene can be calculated by vector addition of the individual $C-Cl$ bond moments.The resultant dipole moment of the two $Cl$ atoms at the $1$ and $3$ positions is equal to the dipole moment of chlorobenzene $(1.5 \ D)$ because the angle between them is $120^{\circ}$ (vector sum of two equal vectors at $120^{\circ}$ is equal to the magnitude of one vector).This resultant vector is directed along the same axis as the $C-Cl$ bond at the $2$ position.Therefore,the total dipole moment is the sum of the resultant of the $1,3-Cl$ atoms and the $2-Cl$ atom,which is $1.5 \ D + 1.5 \ D = 3.0 \ D$.

If the dipole moment of $Images-1$ is $1.5 \ D$,then the dipole moment of $Images-2$ will be .................. $D$.

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