Which of the following is the correct order o | vedclass

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(A) The bond angle depends on the electronegativity of the central atom and the presence of lone pairs. $1$. For $NH_3$ $(107^\circ)$ and $H_2O$ $(104

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$NH_3 > H_2O > PH_3 > H_2S$

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(A) The bond angle depends on the electronegativity of the central atom and the presence of lone pairs. $1$. For $NH_3$ $(107^\circ)$ and $H_2O$ $(104.5^\circ)$,the central atoms are $N$ and $O$ (period $2$). $2$. For $PH_3$ $(93.5^\circ)$ and $H_2S$ $(92^\circ)$,the central atoms are $P$ and $S$ (period $3$). $3$. Elements in period $2$ have higher electronegativity and smaller size,leading to greater repulsion between bond pairs compared to period $3$ elements. $4$. Thus,the bond angles of $NH_3$ and $H_2O$ are significantly larger than those of $PH_3$ and $H_2S$. $5$. Comparing $NH_3$ and $H_2O$: $NH_3$ has one lone pair,while $H_2O$ has two lone pairs,resulting in more repulsion in $H_2O$ and a smaller bond angle. $6$. Comparing $PH_3$ and $H_2S$: $PH_3$ has one lone pair and $H_2S$ has two,leading to a similar trend. $7$. The correct order is $NH_3 > H_2O > PH_3 > H_2S$.

Which of the following is the correct order of bond angles?

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