C_2H_5Br xrightarrow{aq.,NaOH} X xrightarrow[ | vedclass

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(B) Step $1$: $C_2H_5Br$ reacts with aqueous $NaOH$ via nucleophilic substitution $(S_N2)$ to form ethanol $(C_2H_5OH)$.$C_2H_5Br + NaOH(aq) \rightarr

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Acetic acid

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(B) Step $1$: $C_2H_5Br$ reacts with aqueous $NaOH$ via nucleophilic substitution $(S_N2)$ to form ethanol $(C_2H_5OH)$.$C_2H_5Br + NaOH(aq) \rightarrow C_2H_5OH + NaBr$Step $2$: Ethanol $(C_2H_5OH)$ is a primary alcohol,which upon oxidation with acidic potassium dichromate $(Na_2Cr_2O_7 / H_2SO_4)$ gets oxidized to acetic acid $(CH_3COOH)$.$C_2H_5OH + [O] \xrightarrow{Na_2Cr_2O_7 / H_2SO_4} CH_3COOH$Therefore,$[Y]$ is acetic acid.

$C_2H_5Br$ $\xrightarrow{aq.\,NaOH} X$ $\xrightarrow[H_2SO_4]{Na_2Cr_2O_7} Y$
$[Y]$ is

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$C_2H_5Br$ $\xrightarrow{aq.\,NaOH} X$ $\xrightarrow[H_2SO_4]{Na_2Cr_2O_7} Y$$[Y]$ is