A and B are two metallic rings placed at oppo | vedclass

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(B) $1$. According to the right-hand thumb rule,the magnetic field produced by the current in the wire is directed into the page on the right side (ne

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Anticlockwise in $A$ and clockwise in $B$

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(B) $1$. According to the right-hand thumb rule,the magnetic field produced by the current in the wire is directed into the page on the right side (near ring $B$) and out of the page on the left side (near ring $A$).$2$. When the current in the wire decreases,the magnetic flux through both rings decreases.$3$. According to Lenz's law,the induced current will oppose this change by creating its own magnetic field to support the decreasing flux.$4$. For ring $A$ (left side),the magnetic field is outward and decreasing. To support this,the induced current will flow in an anticlockwise direction to produce an outward magnetic field.$5$. For ring $B$ (right side),the magnetic field is inward and decreasing. To support this,the induced current will flow in a clockwise direction to produce an inward magnetic field.$6$. Therefore,the induced current is anticlockwise in $A$ and clockwise in $B$.

$A$ and $B$ are two metallic rings placed at opposite sides of an infinitely long straight conducting wire as shown. If current in the wire is slowly decreased,the direction of induced current will be

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