Benzene xrightarrow[H_2SO_4]{HNO_3} (A) xrigh | vedclass

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(A) $1$. The reaction of $Benzene$ with $HNO_3$ in the presence of $H_2SO_4$ is a nitration reaction,which yields $Nitrobenzene$ as product $(A)$.$2$.

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(A) $1$. The reaction of $Benzene$ with $HNO_3$ in the presence of $H_2SO_4$ is a nitration reaction,which yields $Nitrobenzene$ as product $(A)$.$2$. $Nitrobenzene$ contains a $-NO_2$ group,which is a strongly deactivating and meta-directing group.$3$. When $(A)$ $(Nitrobenzene)$ reacts with $Cl_2$ in the presence of a Lewis acid catalyst like $FeCl_3$,electrophilic aromatic substitution occurs.$4$. Due to the meta-directing nature of the $-NO_2$ group,the incoming chlorine atom attaches to the meta position relative to the $-NO_2$ group.$5$. Thus,the major product $(B)$ is $m-Chloronitrobenzene$.

$Benzene$ $\xrightarrow[H_2SO_4]{HNO_3} (A)$ $\xrightarrow[FeCl_3]{Cl_2} (B)$
The major product $(B)$ is

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$Benzene$ $\xrightarrow[H_2SO_4]{HNO_3} (A)$ $\xrightarrow[FeCl_3]{Cl_2} (B)$The major product $(B)$ is