The $EN$ (Electronegativity) of element $A$ is $E_1$ and its $IP$ (Ionization Potential) is $E_2$. Hence,the $EA$ (Electron Affinity) will be:

  • A
    $2E_1 - E_2$
  • B
    $E_1 - E_2$
  • C
    $E_1 - 2E_2$
  • D
    $(E_1 + E_2) / 2$

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Similar Questions

Given below are two statements:
Statement $I$: The correct order of electronegativity of fluorine, oxygen and nitrogen is $F > O > N$.
Statement $II$: The oxidation state of oxygen in $OF_2$ is $+2$ and in $Na_2O$ is $-2$.

Which one of the following correctly represents the variation of electronegativity $(EN)$ with atomic number $(Z)$ of group $13$ elements?

Going from fluorine to chlorine,bromine and iodine,the electronegativity

Let electronegativity,ionisation energy and electron affinity be represented as $EN$,$IP$ and $EA$ respectively. Which one of the following equations is correct according to Mulliken?

The element with the highest electronegativity value after fluorine $(F)$ is:

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