Going from fluorine to chlorine,bromine and iodine,the electronegativity

Among $Me_{3}N$, $C_{5}H_{5}N$ and $MeCN$ $(Me = \text{methyl group})$, the electronegativity of $N$ is in the order:

In the compound $M-O-H$,the $M-O$ bond will be broken if

Aqueous solutions of two compounds $M_1-OH$ and $M_2-OH$ are prepared in two different beakers. If the electronegativity of $M_1 = 3.4$,$M_2 = 1.2$,$O = 3.5$,and $H = 2.1$,then the nature of the two solutions will be respectively:

Which of the following elements has the highest electronegativity?

The values of electronegativity of atoms $A$ and $B$ are $1.20$ and $4.0$ respectively. The percentage of ionic character of $A-B$ bond is ............. $\%$