In the compound M-O-H,the M-O bond will be br | vedclass

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(C) In the compound $M-O-H$,the cleavage of the bond depends on the electronegativity difference. If the electronegativity difference between $M$ and

Vedclass · Accepted Answer

$\Delta (E.N.)$ of $M$ and $O > \Delta (E.N.)$ of $O$ and $H$

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(C) In the compound $M-O-H$,the cleavage of the bond depends on the electronegativity difference. If the electronegativity difference between $M$ and $O$ is greater than the electronegativity difference between $O$ and $H$,the $M-O$ bond is more polar and breaks to form $M^+$ and $OH^-$ ions. Therefore,the $M-O$ bond breaks if $\Delta (E.N.)$ of $M$ and $O > \Delta (E.N.)$ of $O$ and $H$.

In the compound $M-O-H$,the $M-O$ bond will be broken if

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