Electronegativity of beryllium $(Be)$ is approximately equal to that of

Given below are two statements:
Statement $I$: The correct order of electronegativity of fluorine, oxygen and nitrogen is $F > O > N$.
Statement $II$: The oxidation state of oxygen in $OF_2$ is $+2$ and in $Na_2O$ is $-2$.

Which of the following bonds has the most polar character?

The correct option with respect to the Pauling electronegativity values of the elements is

The increasing order of electronegativity is:

The values of electronegativity of atoms $A$ and $B$ are $1.20$ and $4.0$ respectively. The percentage of ionic character of $A-B$ bond is ............. $\%$