Which of the following complexes does not exh | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) $1$. In $[CoF_6]^{3-}$,the oxidation state of $Co$ is $+3$. The electronic configuration of $Co^{3+}$ is $[Ar] 3d^6$. $F^-$ is a weak field ligand

Vedclass · Accepted Answer

$[CoF_6]^{3-}$

Vedclass · Answer

(A) $1$. In $[CoF_6]^{3-}$,the oxidation state of $Co$ is $+3$. The electronic configuration of $Co^{3+}$ is $[Ar] 3d^6$. $F^-$ is a weak field ligand,so it does not cause pairing of electrons. Thus,it undergoes $sp^3d^2$ hybridization (outer orbital complex).$2$. In $[Co(NH_3)_6]^{3+}$,$Co^{3+}$ is $[Ar] 3d^6$. $NH_3$ is a strong field ligand,causing pairing of electrons in $3d$ orbitals,leading to $d^2sp^3$ hybridization.$3$. In $[Fe(CN)_6]^{3-}$,$Fe^{3+}$ is $[Ar] 3d^5$. $CN^-$ is a strong field ligand,causing pairing,leading to $d^2sp^3$ hybridization.$4$. In $[Cr(NH_3)_6]^{3+}$,$Cr^{3+}$ is $[Ar] 3d^3$. It utilizes two $3d$ orbitals,one $4s$ orbital,and three $4p$ orbitals to form $d^2sp^3$ hybridization.$5$. Therefore,$[CoF_6]^{3-}$ is the only complex that exhibits $sp^3d^2$ hybridization instead of $d^2sp^3$.

Which of the following complexes does not exhibit $d^2sp^3$ hybridization?

Similar Questions

Which of the following is a square planar complex ion?

The geometry of $Ni(CO)_4$ and $Ni(PPh_3)_2Cl_2$ are

Consider the reaction $K_2[Ni(CN)_4] + 4K + 4NH_3 \to A$ (complex $A$).
Complex $A$ gives five ions in aqueous solution. Choose the $CORRECT$ statements.

The geometry of the cuprammonium ion $[Cu(NH_3)_4]^{2+}$ is:

The hybridisation and geometry of $[Ni(CN)_4]^{2-}$ are:

Vedclass Test Series

Exam Paper Generator

Online Exam Module