The complex ion $[Co(C_2O_4)_3]^{3-}$ has which of the following hybridizations?

  • A
    $sp^3d^2$
  • B
    $d^2sp^3$
  • C
    $sp^2d^3$
  • D
    $d^3sp^2$

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Similar Questions

Match List-$I$ with List-$II$.
List-$I$ List-$II$
$A$. $[MnBr_4]^{2-}$ $I$. $d^2sp^3$ and diamagnetic
$B$. $[FeF_6]^{3-}$ $II$. $sp^3d^2$ and paramagnetic
$C$. $[Co(C_2O_4)_3]^{3-}$ $III$. $sp^3$ and diamagnetic
$D$. $[Ni(CO)_4]$ $IV$. $sp^3$ and paramagnetic

Choose the correct answer from the options given below:

Addition of excess aqueous ammonia to a pink coloured aqueous solution of $MCl_2 \cdot 6H_2O (X)$ and $NH_4Cl$ gives an octahedral complex $Y$ in the presence of air. In aqueous solution,complex $Y$ behaves as a $1:3$ electrolyte. The reaction of $X$ with excess $HCl$ at room temperature results in the formation of a blue coloured complex $Z$. The calculated spin-only magnetic moment of $X$ and $Z$ is $3.87 \ B.M.$,whereas it is zero for complex $Y$.
Among the following options,which statement$(s)$ is(are) correct?
$[A]$ The hybridization of the central metal ion in $Y$ is $d^2sp^3$
$[B]$ $Z$ is a tetrahedral complex
$[C]$ Addition of silver nitrate to $Y$ gives only two equivalents of silver chloride
$[D]$ When $X$ and $Z$ are in equilibrium at $0^{\circ}C$,the colour of the solution is pink

In an octahedral structure,which pair of $d$-orbitals is involved in ${d^2}sp^3$ hybridization?

Match List-$I$ with List-$II$ and select the correct answer using the codes given below the lists $:$
List-$I$ $(Compounds)$List-$II$ $(Hybridization)$
$(a)$ $[Ni(NH_3)_6]^{+2}$$(i)$ $sp^3 d^2$
$(b)$ $[PtCl_4]^{-2}$$(ii)$ $dsp^2$
$(c)$ $[Ni(CO)_4]$$(iii)$ $sp^3$
$(d)$ $[Co(OX)_3]^{-3}$$(iv)$ $d^2 sp^3$

Briefly explain the Valence Bond Theory $(VBT)$.

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