In the reaction CH_2 = CH_2 xrightarrow[text{ | vedclass

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(A) $1$. The reaction of ethene $(CH_2=CH_2)$ with hypochlorous acid $(HOCl)$ follows electrophilic addition to form $2$-chloroethanol $(M = CH_2Cl-CH

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$CH_2Cl-CH_2OH$ and $NaOH(aq)$

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(A) $1$. The reaction of ethene $(CH_2=CH_2)$ with hypochlorous acid $(HOCl)$ follows electrophilic addition to form $2$-chloroethanol $(M = CH_2Cl-CH_2OH)$.$2$. $2$-chloroethanol $(CH_2Cl-CH_2OH)$ reacts with aqueous sodium hydroxide $(NaOH)$ via an intramolecular nucleophilic substitution reaction (or hydrolysis) to form ethylene glycol $(CH_2OH-CH_2OH)$.$3$. Therefore,$M$ is $CH_2Cl-CH_2OH$ and $R$ is $NaOH(aq)$.

In the reaction $CH_2 = CH_2$ $\xrightarrow[\text{acid}]{\text{Hypochlorous}} M$ $\xrightarrow{R} \begin{array}{c} CH_2OH \\ | \\ CH_2OH \end{array}$,$M$ and $R$ are respectively:

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